众所周知
符合这个条件的数
就是大于2的偶数[doge]
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
if (n == 2 || n % 2 == 1) {
cout << "NO, you can't divide the watermelon into two even parts.";
} else {
cout << "YES, you can divide the watermelon into two even parts.";
}
return 0;
}